Answer to Question #313939 in Calculus for Adeboye

Question

Differentiate y= In ( 2cot²x )

Answer 1

$y'=\frac{1}{2cot^2(x)}\cdot 2\cdot2cot(x)\cdot (-\frac{1}{sin^2(x)})=\\ =-\frac{2}{sin^2(x)cot(x)}=-\frac{2}{sinxcosx}$