Slope of the line y+2x=0: m=-2.
Slope of the tangent: y′=1−x21.
We have: y′=m or 1−x21=−2.
So, x=31,x=−31.
y(31)=31+3.
y(−31)=−31−3.
Equations of the tangent lines:
y−31−3=−2(x−31) or y=−2x+23 .
y+31+3=−2(x+31) or y=−2x−23.
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