Question #278669

Give an example of a function of two variables such that f(0,0) = 0 but f is NOT continuous at (0,0). Explain why the function f is NOT continuous at (0,0).


1
Expert's answer
2021-12-15T16:20:19-0500

f(x,y)={2xyx2+y2(x,y)(0,0)0(x,y)=(0,0)f(x,y)=\begin{cases} \frac{2xy}{x^2+y^2} &(x,y) \neq (0,0) \\ 0 &(x,y)=(0,0) \end{cases}


Choosing the path x = 0 we see that f (0, y) = 0, so

limy0f(0,y)=0\displaystyle\lim_{y→0} f (0, y) = 0

Choosing the path x = y we see that

f(x,x)=2x2/2x2=1f (x, x) = 2x^ 2 /2x^ 2 = 1

so

limx0f(x,x)=1\displaystyle\lim_{x→0} f (x,x) = 1

The Two-Path Theorem (if a function has two different limits along two different paths) implies that

lim(x,y)(0,0)f(x,y)\displaystyle\lim_{(x,y)→(0,0)} f (x,y)

does not exist.



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