Answer to Question #271770 in Calculus for Sara

Question #271770

Suppose that a population yy grows according to the logistic model given by formula:



yy = LL


1 + AAee−kkkk .


a. At what rate is yy increasing at time tt = 0 ?


b. In words, describe how the rate of growth of yy varies with time.


c. At what time is the population growing most rapidly?

1
Expert's answer
2021-11-29T14:59:25-0500

y=l1+Aekty=\frac{l}{1+Ae^{-kt}}


a) dydt=lAekt(k)(1+Aekt)2\frac{dy}{dt}=\frac{-l\cdot Ae^{-kt}(-k)}{(1+Ae^{-kt})^2}

=klAekt(1+Aekt)2=\frac{klAe^{-kt}}{(1+Ae^{-kt})^2}

y(t=0)=kAl(1+A)2y'(t=0)=\frac{kAl}{(1+A)^2}

y is increasing at a rate of kAl(1+A)2\frac{kAl}{(1+A)^2}

b) The rate of growth is always positive meaning y will increase with increase in t

c) y=(1+Aekt)2(k2Alekt)kAlekt2(1+Aekt)(kA)(1+Aekt)4=0y''=\frac{(1+Ae^{-kt})^2(-k^2Ale^{-kt})-kAle^{-kt}\cdot 2(1+Ae^{-kt})(-kA)}{(1+Ae^{-kt})^4}=0

    (1+Aekt)(1)+(+2)=0\implies(1+Ae^{-kt})(-1)+(+2)=0

    1+Aekt=2\implies 1+Ae^{-kt}=2

ekt=1Ae^{-kt}=\frac{1}{A}

t=ln1Akt=\frac{ln{\frac{1}{A}}}{-k}

Population is growing most rapidly at t=ln1Akt=\frac{ln{\frac{1}{A}}}{-k}


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