y=1+Ae−ktl
a) dtdy=(1+Ae−kt)2−l⋅Ae−kt(−k)
=(1+Ae−kt)2klAe−kt
y′(t=0)=(1+A)2kAl
y is increasing at a rate of (1+A)2kAl
b) The rate of growth is always positive meaning y will increase with increase in t
c) y′′=(1+Ae−kt)4(1+Ae−kt)2(−k2Ale−kt)−kAle−kt⋅2(1+Ae−kt)(−kA)=0
⟹(1+Ae−kt)(−1)+(+2)=0
⟹1+Ae−kt=2
e−kt=A1
t=−klnA1
Population is growing most rapidly at t=−klnA1
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