Question

With what velocity must an object. Be thrown vertically upward or authority in the maximum height of 900ft from its starting point.

Answer 1

$v^2=u^2-2gh$

But u=0

$v^2=-2gh$

h=900ft=274.32m

$\therefore v^2=-2*-9.81*274.32$

$v^2=5382.1584$

$v=\sqrt{5382.1584}$

$v=73.36m/s$