Question #269137

In a right circular cone, the radius of the base is half as long as the altitude. If an error of 2% is made in measuring the radius, find the percentage of error made in the computed volume.

Expert's answer

Let hh be the altitude and rr be the radius of the base of a right circular cone.

Given: h=2rh=2r  and Δr/r=0.02.\Delta r/r=0.02. inches.

We know that the volume of the right circular is V=13πr2h.V=\dfrac{1}{3}\pi r^2h.

Now h=2r⇒V=13πr2(2r)=23πr3.h=2r\Rightarrow V=\dfrac{1}{3}\pi r^2(2r)=\dfrac{2}{3}\pi r^3.

Take the differentials on both sides


dV=2πr2drdV=2\pi r^2dr

Then


dVV=2πr2dr23πr3=3drr=3(0.02)=0.06\dfrac{dV}{V}=\dfrac{2\pi r^2dr}{\dfrac{2}{3}\pi r^3}=3\dfrac{dr}{r}=3(0.02)=0.06

The percentage of error made in the computed volume is 6%.



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