Differentiate the function π(π₯) = 5π₯ 2 + 2 using the first principle
"=\\lim\\limits_{h\\to 0}\\dfrac{5(x+h)^2+2-(5x^2+2)}{h}"
"=\\lim\\limits_{h\\to 0}\\dfrac{5x^2+10xh+5h^2+2-5x^2-2}{h}"
"=\\lim\\limits_{h\\to 0}(10x+5h)=10x+0=10x"
"f'(x)=(5x^2+2)' =10x"
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