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Question #268653
Differentiate the function 𝑓(𝑥) = 5𝑥 2 + 2 using the first principle
Expert's answer
f
′
(
x
)
=
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
f'(x)=\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}
f
′
(
x
)
=
h
→
0
lim
h
f
(
x
+
h
)
−
f
(
x
)
=
lim
h
→
0
5
(
x
+
h
)
2
+
2
−
(
5
x
2
+
2
)
h
=\lim\limits_{h\to 0}\dfrac{5(x+h)^2+2-(5x^2+2)}{h}
=
h
→
0
lim
h
5
(
x
+
h
)
2
+
2
−
(
5
x
2
+
2
)
=
lim
h
→
0
5
x
2
+
10
x
h
+
5
h
2
+
2
−
5
x
2
−
2
h
=\lim\limits_{h\to 0}\dfrac{5x^2+10xh+5h^2+2-5x^2-2}{h}
=
h
→
0
lim
h
5
x
2
+
10
x
h
+
5
h
2
+
2
−
5
x
2
−
2
=
lim
h
→
0
(
10
x
+
5
h
)
=
10
x
+
0
=
10
x
=\lim\limits_{h\to 0}(10x+5h)=10x+0=10x
=
h
→
0
lim
(
10
x
+
5
h
)
=
10
x
+
0
=
10
x
f
′
(
x
)
=
(
5
x
2
+
2
)
′
=
10
x
f'(x)=(5x^2+2)' =10x
f
′
(
x
)
=
(
5
x
2
+
2
)
′
=
10
x
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#340153
on Dec 2023
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