(1)Σn=1∞arn−1=3−1<r<1 isS=1−ra1
where a=first term & r=common ratio
S=3
3=1−ra
therefore
r=33−a
For a series to converge:−1<r<1
−1<r<1
−1<33−a<1
−3<3−a<3
−6<−a<0
0<a<6
final answerFor the series to converge,0<a<6 and−1<r<1.
(2) 1−2+2!4−3!8+4!16−5!32+6!64−7!128+−−++n!−2n+−−
=e−2=0.135
=0.135
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