Question #258018

After eight years of dating, a female broke up with her lover on a rainy day. They chose to split up in the same area where everything about them began. The boy is crying and rushing north at a speed of 5 feet per second, while the girl is strolling east at a speed of 1 foot per second, wondering if she made the right decision. 5 seconds after they started traveling to a new life without each other, how quickly are they detaching from each other?


Expert's answer

Distance traveled by the boy is 5t5t feet. Distance traveled by the girl is 1t1t feet.

By the Pythagorean Theorem distance ss between them is


s(t)=(5t)2+(1t)2=26t(ft)s(t)=\sqrt{(5t)^2+(1t)^2}=\sqrt{26}t(ft)

How quickly are they detaching from each other


v(t)=s(t)=(26t)=26(ft/sec)v(t)=s'(t)=(\sqrt{26}t)'=\sqrt{26} (ft/sec)

They are detaching from each other at a spped of 26\sqrt{26} from each other.


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