Question #252848
The cable of a suspension bridge hangs in the shape of a parabola . The towers supporting the cable are 400 ft apart and 150 ft high. If the cable , at its lowest , 30 ft above the bridge at its midpoint , how high is the cable 50ft away (horizontally) from either tower?
1
Expert's answer
2021-10-18T17:06:49-0400

Let the lies in the middle between two towers.

The equation of parabola will be y=ax2+b.y=ax^2+b.

y(0)=30b=30.y(0)=30\to b=30.

y(200)=15040000a+30=150a=12040000=0.003.y(200)=150\to 40000a+30=150\to a=\frac{120}{40000}=0.003.

Thus, the equation of parabola: y=0.003x2+30.y=0.003x^2+30.

y(20050)=y(150)=0.0031502+30=97.5.y(200-50)=y(150)=0.003*150^2+30=97.5.

The cable is 97.5 ft high 50 ft away from either tower.


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