Question #252680

Let the š’‡(š’™, š’š) = { š’„š’š’”š’š. š’”š’Šš’š’™, š’™ ≠ šŸŽ š’„š’š’”š’š, š’™ = šŸŽ }. Is š’‡(š’™, š’š) continues at (šŸŽ, šŸŽ)? Is š’‡(š’™, š’š) continues everywhere?


Expert's answer

The function has the form: f(x,y)=cos y  sin x,  x≠0f(x,y)=cos\,y\,\,sin\,x,\,\,x\neq0 and f(x,y)=cos y,  x=0f(x,y)=cos\,y,\,\, x=0. Set y=0y=0Then, f(x,y)=1f(x,y)=1 at x=0,y=0x=0,y=0 and f(x,y)=sin xf(x,y)=sin\,x if x≠0x\neq0. But sin xsin\,x approaches 0 as xx tends to .Thus, the function is not continuous at x=0,y=0.x=0,y=0.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS