Question #249193

Find the first partial derivative zx\displaystyle{\frac{\partial z}{ \partial x}} ​ of the function z=x2eyz=x^2e^{-y} at point  (2,-1)


1
Expert's answer
2021-10-11T15:47:53-0400

zx=2xey\frac{\partial z}{\partial x}=2xe^{-y}


zx(2,1)=22e1=4/e\frac{\partial z}{\partial x}|_{(2,-1)}=2\cdot2e^{-1}=4/e


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