Find the first partial derivative ∂z∂x\displaystyle{\frac{\partial z}{ \partial x}}∂x∂z of the function z=x2e−yz=x^2e^{-y}z=x2e−y at point (2,-1)
∂z∂x=2xe−y\frac{\partial z}{\partial x}=2xe^{-y}∂x∂z=2xe−y
∂z∂x∣(2,−1)=2⋅2e−1=4/e\frac{\partial z}{\partial x}|_{(2,-1)}=2\cdot2e^{-1}=4/e∂x∂z∣(2,−1)=2⋅2e−1=4/e
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