Question #244993

Find the linearization of the function f(x,y) = ye^x + 2x^2 y at the point (0,2) and use the result to approximate f (0.1, 1.9) to three decimal places.


1
Expert's answer
2021-10-01T15:08:49-0400

L(x,y)=f(a,b)+f(x,y)xa,b(xa)+f(x,y)ya,b(yb)L(x,y)=f(a,b)+\frac{\partial f(x,y)}{\partial x}|_{a,b}(x-a)+\frac{\partial f(x,y)}{\partial y}|_{a,b}(y-b)


f(0,2)=2f(0,2)=2

fx=yex+4xyf_x=ye^x+4xy

fx(0,2)=2f_x(0,2)=2

fy=ex+2x2f_y=e^x+2x^2

fy(0,2)=1f_y(0,2)=1


L(x,y)=2+2x+y2=2x+yL(x,y)=2+2x+y-2=2x+y


f(0.1,1.9)=0.2+1.9=2.100f(0.1,1.9)=0.2+1.9=2.100


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