Question

Let the displacement function of a moving object is S(t)= 5t^3-3t^2+6t. What is the function for the velocity of the object at time t.

Answer 1

Given that: $S(t)= 5t^3-3t^2+6t$

We know that: Velocity $V(t)$ is given as: $\frac{d(S(t))}{dt}$

$\therefore V(t)=15t^2-6t+6$