Question #242035

When two given functions, š‘“(š‘„) = š‘„ 2 + 3 š‘Žš‘›š‘‘ š‘”(š‘„) = 2š‘„ āˆ’ 5, are divided with each other, a new third function is obtained. Find (š‘“/š‘”)(š‘„) and identify its domain


Expert's answer

When two given functions, š‘“(š‘„)=š‘„2+3š‘“(š‘„) = š‘„^2 + 3 and š‘”(š‘„)=2š‘„āˆ’5š‘”(š‘„) = 2š‘„ āˆ’ 5, are divided with each other, a new third function is obtained: (š‘“/š‘”)(š‘„)=x2+32xāˆ’5.(š‘“/š‘”)(š‘„)=\frac{x^2+3}{2x-5}. Let us identify its domain. Since the denominator of x2+32xāˆ’5\frac{x^2+3}{2x-5} is equal to zero in the point x=2.5,x=2.5, we conclude that the domain of the function (š‘“/š‘”)(š‘„)(š‘“/š‘”)(š‘„) is (āˆ’āˆž,2.5)∪(2.5,+āˆž).(-\infty,2.5)\cup(2.5,+\infty).


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