Which of the following represents the integral "{\\int \\frac{1}{x\\ln{x}}dx}"
1) "ln(lnx)+C"
2) "ln(xlnx)+C"
3) "lnxlnx+C"
4) None of the above
"\\smallint\\frac{1}{xln(x)}dx"
Substitute "u=ln(x)"
Hence "\\frac{du}{dx}=\\frac{1}{x}," "dx=xdu."
Therefore, = "\\smallint\\frac{1}{u}du"
This the standard integral;
"=ln(u)+C"
Undo substitution "u=ln(x)"
"=ln(ln(x))+C"
Hence the answer is "ln(lnx)+C"
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