Answer to Question #225422 in Calculus for Anuj

Question #225422

Question:

If π‘Ž and 𝑏 are two sides of a right angled hypotenuse 𝑐 and let 𝑝 be the perpendicular from the opposite

vertex on the hypotenuse, show that:

1. (𝛿 𝑝/π›Ώπ‘Ž)b =b3/c3

2. (𝛿𝑝/π›Ώπ‘Ž )A=b/c



1
Expert's answer
2021-08-17T09:39:20-0400

Part 1

From Pythagoras theorem

c2=a2+b2c^2=a^2+b^2\\

From the similarity of triangles

pa=bc\frac{p}{a}=\frac{b}{c}

When we differentiate partially with respect to a

βˆ‚pβˆ‚a=bc\frac{\partial p}{\partial a}=\frac{b}{c}

Cubing each side of the equation and neglecting the smallest differentials we get

βˆ‚pβˆ‚a=(bc)3βˆ‚pβˆ‚a=b3c3\frac{\partial p}{\partial a}=(\frac{b}{c})^3\\ \frac{\partial p}{\partial a}=\frac{b^3}{c^3}


Part 2

From Pythagoras theorem

c2=a2+b2c^2=a^2+b^2\\

From the similarity of triangles

pa=bc\frac{p}{a}=\frac{b}{c}

When we differentiate partially with respect to a

βˆ‚pβˆ‚a=bc\frac{\partial p}{\partial a}=\frac{b}{c}


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