Question:
If π and π are two sides of a right angled hypotenuse π and let π be the perpendicular from the opposite
vertex on the hypotenuse, show that:
1. (πΏ π/πΏπ)bΒ =b3/c3
2. (πΏπ/πΏπ )A=b/c
Part 1
From Pythagoras theorem
"c^2=a^2+b^2\\\\"
From the similarity of triangles
"\\frac{p}{a}=\\frac{b}{c}"
When we differentiate partially with respect to a
"\\frac{\\partial p}{\\partial a}=\\frac{b}{c}"
Cubing each side of the equation and neglecting the smallest differentials we get
"\\frac{\\partial p}{\\partial a}=(\\frac{b}{c})^3\\\\\n\\frac{\\partial p}{\\partial a}=\\frac{b^3}{c^3}"
Part 2
From Pythagoras theorem
"c^2=a^2+b^2\\\\"
From the similarity of triangles
"\\frac{p}{a}=\\frac{b}{c}"
When we differentiate partially with respect to a
"\\frac{\\partial p}{\\partial a}=\\frac{b}{c}"
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