Question:
If π and π are two sides of a right angled hypotenuse π and let π be the perpendicular from the opposite
vertex on the hypotenuse, show that:
1. (πΏ π/πΏπ)b =b3/c3
2. (πΏπ/πΏπ )A=b/c
Part 1
From Pythagoras theorem
From the similarity of triangles
When we differentiate partially with respect to a
Cubing each side of the equation and neglecting the smallest differentials we get
Part 2
From Pythagoras theorem
From the similarity of triangles
When we differentiate partially with respect to a
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