. Find the limits lim (𝑥,𝑦)→(2,−4) 𝑦+4 𝑥 2𝑦−𝑥𝑦+4𝑥 2−4�
We need to find lim(x,y)→lim(x,y)\tolim(x,y)→ (2,−4)(2,-4)(2,−4) (y+4x)(2y−xy+4x)\frac {(y+4x)} {(2y-xy+4x)}(2y−xy+4x)(y+4x)
We will do direct substitution to find the limit .
=== (−4+4(2))(2(−4)−2(−4)+4(2))\frac{(-4+4(2))} {(2(-4)-2(-4)+4(2))}(2(−4)−2(−4)+4(2))(−4+4(2))
=(−4+8)(−8+8+8)=\frac {(-4+8)} {(-8+8+8)}=(−8+8+8)(−4+8)
=48=\frac 4 8=84 =12=\frac 1 2=21 (ans)
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