. Find the limits lim (π₯,π¦)β(2,β4) π¦+4 π₯ 2π¦βπ₯π¦+4π₯ 2β4οΏ½
We need to find lim(x,y)βlim(x,y)\tolim(x,y)β (2,β4)(2,-4)(2,β4) (y+4x)(2yβxy+4x)\frac {(y+4x)} {(2y-xy+4x)}(2yβxy+4x)(y+4x)β
We will do direct substitution to find the limit .
=== (β4+4(2))(2(β4)β2(β4)+4(2))\frac{(-4+4(2))} {(2(-4)-2(-4)+4(2))}(2(β4)β2(β4)+4(2))(β4+4(2))β
=(β4+8)(β8+8+8)=\frac {(-4+8)} {(-8+8+8)}=(β8+8+8)(β4+8)β
=48=\frac 4 8=84β =12=\frac 1 2=21β (ans)
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