Question #208818
Use implicit defferentiation to determine the derivative of the equation of the eclipse below: 
(X/a)^2+(y/b)^2=1




1
Expert's answer
2021-06-22T14:43:15-0400
(x/a)2+(y/b)2=1(x/a)^2+(y/b)^2=1

Differentiate both sides with respect to xx


ddx((xa)2+(yb)2)=ddx(1)\dfrac{d}{dx}((\dfrac{x}{a})^2+(\dfrac{y}{b})^2)=\dfrac{d}{dx}(1)

Use the Chain Rule


2xa2+2yb2dydx=0\dfrac{2x}{a^2}+\dfrac{2y}{b^2}\cdot\dfrac{dy}{dx}=0

Solve for dydx\dfrac{dy}{dx}

dydx=b2xa2y\dfrac{dy}{dx}=-\dfrac{b^2x}{a^2y}


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