Answer to Question #205264 in Calculus for ken

Question

Evaluate subject to the functional relation x=t³ and y=t².

Answer 1

Given x = t³ and y = t²

Differentiation is a functional relation of x and y.

So, Differentiating x and y with respect to t

dx/dt = 3t²

dy/dt = 2t

Now functional relation is, dy/dx = (dy/dt)/(dx/dt) = 2t/3t² = 2/3t

Thus, the functional relation of x and y is

dy/dx = 2/3t