Question #205065

Question 1


Find the derivative of

y = ln 3x5.

 

a.    ln 3x5

b.    15x4

c.    5x−1

d. 1/

3x5

 


Question  2

Find the derivative of the function


a.    x2/ x + x/ x

b. x2 + x /x

c. 2x + 1

d.    3x4 + 2x3

 


Question  3

Differentiate the function

f (x) = 3x3e2x.


a. 5x4e3x

b. 3x2e2x(x − 3)

c. 3e3x + 9x4x5

d. 3x2e2x(2x + 3)


Question  4

The total revenue function (TR), in terms of P and the company's quantity, if a commodity sells for R199.00  are?

a. TR = 6 000 − 30P ; Q = 30.

b. TR = 6 000P − 30P 2; Q = 30.

c. TR = P (6 000 − 30P ); Q = 24.

d.  TR = 6 000 − 30P ; Q = 24.

 



1
Expert's answer
2022-01-10T14:38:19-0500

1.

y=15x43x5=5x1y' =\frac{15x^4}{3x^5}=5x^{-1}


Answer: c. 5x−1


2.

y=x2+xy=x^2+x

y=2x+1y'=2x+1


Answer: c. 2x + 1


3.

f(x)=9x2e2x+6x3e2x=3x2e2x(2x+3)f' (x) =9x^2e^{2x}+ 6x^3e^{2x}=3x^2e^{2x}(2x + 3)


Answer: d. 3x2e2x(2x + 3)


4.

The total revenue function (TR), in terms of P and the company's quantity, if a commodity sells for R199.00 are?

TR=QP=6000P30P2TR = Q P = 6 000 P - 30 P^2

Q=600030P=600030199=30Q = 6 000 - 30 P = 6 000 - 30 \cdot199 = 30


Answer: b. TR = 6 000P − 30P 2; Q = 30


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