dxd[x2+1earcsin(x)]=(x2+1)2dxd[earcsin(x)]⋅(x2+1)−earcsin(x)⋅dxd[x2+1]=(x2+1)2earcsin(x)⋅dxd[arcsin(x)]⋅(x2+1)−earcsin(x)(dxd[x2]+dxd[1])=(x2+1)2−(x2+1)earcsin(x)1−x22xearcsin(x) Therefore the derivative is dxdy=1−x2(x2+1)earcsin(x)−(x2+1)22xearcsin(x)
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