Using imlicit differentiation, which one of the following is the derivative of
"cos(x-2y) = sin(2x + y)"
"cos(x\u22122y)=sin(2x+y)\\\\\n\\text{differentiate with respect to x.}\\\\\n\\implies -sin(x\u22122y)(1-2y')=cos(2x+y)(2+y')\\\\\n\\implies\n-sin(x\u22122y)+2sin(x\u22122y)y'-2cos(2x+y)-\ncos(2x+y)y'=0\\\\\n\\implies\ny'=\\frac{sin(x\u22122y)+2cos(2x+y)}{2sin(x\u22122y)-cos(2x+y)}"
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