Question

Determine the derivative of the function $f(x) = x^2sinx$ at $x = π/2$

Answer 1

$$f'(x)=2x\sin x+x^2\cos x$$

$$f'(\dfrac{\pi}{2})=2(\dfrac{\pi}{2})\sin (\dfrac{\pi}{2})+(\dfrac{\pi}{2})^2\cos (\dfrac{\pi}{2})=\pi$$

$$f'(\dfrac{\pi}{2})=\pi$$