Is the function f, defined by f(x)= x^2-5x+4/(x^2-16) , x≠4
f(4)=0, continuous at x=4. Give reasons for your answer.
The function f is continuous at some point c if:
limx→c=f(c)\displaystyle {\lim_{x\to c} }=f(c)x→clim=f(c)
In our case:
limx→4≠f(4)\displaystyle {\lim_{x\to 4} }\ne f(4)x→4lim=f(4)
So, the function f(x) is not continuous at x=4
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