The annual profit for a firm depends upon the number of units produced. the function which describes the relationship between profit P (stated the number of units produced x is
P-0.01x²+5,000x - 25,000
(a) Determine the number of units x which will result in maximum profit. (b) What is the expected maximum profit?
Given Profit-
"P=-0.01x\u00b2+5,000x - 25,000"
Differentiate P w.r.t. x-
"P'=-0.02x+5000"
Putting P'=0, we get-
"-0.02x+5000=0\\\\\\Rightarrow x=\\dfrac{5000}{0.02}=250000"
Again Differentiating P' w.r.t. x-
"P''=-0.05<0,"
P is maximum at x=250000
(a) The unit which results in the maximum profit is 250000.
(b) The expected maximum profit is
"P=-0.01(250000)^2+5000(250000)-25000\\\\=-625000000+1250000000-25000\\\\=624975000"
Comments
Leave a comment