Question

A curve has the equation y=3x^2-5x+4. Find the gradient of the curve at the point (2,6)

Answer 1

y=3x^2-5x+4 ...................Equation(1)

Gradient of a curve at any point (x, y) is given by

m = $\dfrac{dy}{dx}$

Differentiating Equation(1) with respect to x we have,

$\dfrac{dy}{dx}$ = 6x - 5

$\lparen\dfrac{dy}{dx}\rparen$ at x = 2 is equal to

m = 6$*$ 2 - 5

m = 7