Answer to Question #196540 in Calculus for Jean Lyre de Leon

Question #196540

Find the volume generated if the function y= square root of 1-x^2 is revolved around the x-axis (use only the positive area)


1
Expert's answer
2021-05-24T04:12:46-0400

The volume of Revolution about OxO_x is given by:


V=x=bx=aπy2dxV = \int^{x=a}_{x=b}\pi y^2dx

So for this problem, Nothing that 1x2=0    x=±11-x^2 = 0 \implies x = \pm 1 and that by symmetry we can double the volume for the region but we have to consider only positive coordinate.


V=03π(1x2)2dxV = \int_{0}^{3} \pi(\sqrt{1-x^2})^2dx

V=π03(1x2)dxV = \pi \int_{0}^{3}(1-x^2)dx

V=π[xx33]01V = \pi[x-\dfrac{x^3}{3}]_{0}^{1}

V=2π3V = \dfrac{2\pi}{3}


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