Find the volume generated if the function y= square root of 1-x^2 is revolved around the x-axis (use only the positive area)
The volume of Revolution about "O_x" is given by:
"V = \\int^{x=a}_{x=b}\\pi y^2dx"
So for this problem, Nothing that "1-x^2 = 0 \\implies x = \\pm 1" and that by symmetry we can double the volume for the region but we have to consider only positive coordinate.
"V = \\int_{0}^{3} \\pi(\\sqrt{1-x^2})^2dx"
"V = \\pi \\int_{0}^{3}(1-x^2)dx"
"V = \\pi[x-\\dfrac{x^3}{3}]_{0}^{1}"
"V = \\dfrac{2\\pi}{3}"
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