We have given the function,
F(x,y)=x2+xy+y2 over [2,1]×[1,2]
x varies from 2 to 1.
y varies from 1 to 2.
Integrating the given function,
∫12∫21(x2+xy+y2)dxdy
∫12[3x3+2x2y+xy2]21dy
=∫12[−37+25y−y2]dy
=[−37y+45y2−3y3]12
=−1287
Hence, the given function is Integrable over [2,1]×[1,2].
Comments