The function,
f(x,y)= { x ; y is rational
{ 0 ; y is irrational
is integrable or not
True or false with full explanation
Solution:-
Given that f(x,y) = {x ; his rational }.and {0;y is irrational}
In this case we can see that
Function must be integrable
As any function of x and y , and x is dependent on value of x , in this case x is defined when y is rational .
And x is 0 in case of y is irrational.
When x is defined in the domain and y is rational or irrational than the function must be integrabal ,
The condition is -f(x,y) , is defined in the domain , for both x and y .
Then overall function is integrable.
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