Answer to Question #189369 in Calculus for clarisse

Question #189369

Your classmate requests you to help him/her in understanding the solutions of the

lim

t→0

(1−cos3t)/

(3t)

= 0, via writing. How do you apply your knowledge based on what you have


learned from this module in doing the task?


1
Expert's answer
2021-05-07T13:29:01-0400

Ans:-

limt01Cos3t3tlimt01(12Sin23t)3tlimt02Sin23t3t\lim_{t \to 0} \dfrac{1-Cos3t}{3t}\\ \Rightarrow \lim_{t \to 0} \dfrac{1-(1-2Sin^23t)}{3t}\\ \Rightarrow\lim_{t \to 0} \dfrac{2Sin^23t}{3t}\\ \\


limx02×Sin23t×3t(3t)2limt06tlimt0Sin23t(3t)2\Rightarrow \lim_{x \to 0} 2\times\dfrac{Sin^23t\times3t}{(3t)^2}\\ \Rightarrow\lim_{t \to 0}6t\lim_{t \to 0} \dfrac{Sin^23t}{(3t)^2} limt0Sintt=1\because \lim_{t \to 0} \dfrac{Sint}{t}=1


limt06t×1\Rightarrow \lim_{t \to 0}6t \times1 limt0Sin23t(3t)2=1\because \lim_{t \to 0} \dfrac{Sin^23t}{(3t)^2}=1


0\Rightarrow 0 .....Ans



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