Determine the average value of f(x,y) = ex+y over the region R=[0,2]X[0,2].
Let "f(x,y)=e^{x+y}" and "R=[0,2]\\times [0,2]" .
The average value of "f" over "R" is "f_\\text{avg}=\\frac{1}{\\text{Area}_R}\\iint _R f(x,y)dA" .
"\\text{Area}_R=2^2=4"
"\\iint _R f(x,y)dA=\\int\\limits_0^2\\int\\limits_0^2e^{x+y}dxdy=\\int\\limits_0^2 \\int\\limits_0^2 e^{x}\\cdot e^ydx dy=\n\\int\\limits_0^2e^{x}dx \\cdot \\int\\limits_0^2e^ydy=e^x\\big|^2_0\\ \\cdot \\ e^y\\big|_0^2=(e^2-1)^2"
Answer: "f_{\\text{avg}}=\\frac{(e^2-1)^2}{4}" .
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