Consider the relation π = {(1,7), (β1,7), (3,9), (1,3)}. Is π a function? Justify your answer.
Given "\ud835\udc43 = \\{(1,7), (\u22121,7), (3,9), (1,3)\\}"
The domain of the function is:
and the co-domain of the function is:
which doubles as the image/range of the function.
P is a function because every element in the domain is mapped to an element in the co-domain and also, each element in the domain is not a first element to more than one element in the co-domain.
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