Answer to Question #179832 in Calculus for Chan

Question #179832

Prove that 𝑓(π‘₯) = π‘₯ 2 + 2π‘₯ is not injective


1
Expert's answer
2021-04-29T16:47:12-0400

Given,

f(x)=x2+2xf(x)=x^2+2x


x2+2xβˆ’y=0x^2+2x-y=0


The solution of the above equation is-


x=βˆ’2Β±4+4y2x=\dfrac{-2\pm\sqrt{4+4y}}{2}


x=βˆ’1Β±1+yx=-1\pm\sqrt{1+y}


which is defined in R for yβ‰₯βˆ’1.yβ‰₯βˆ’1. This can be used to separate the domain of f(x) into two intervals. For x∈[1,∞x\in[1,∞ ) and x∈(βˆ’βˆž,1]x\in(βˆ’βˆž,1] , the function f(x) is not injective (and invertible). The domain that contains 2 is of course [1,∞).[1,∞).


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