My orders
How it works
Examples
Reviews
Blog
Homework Answers
Submit
Sign in
How it works
Examples
Reviews
Homework answers
Blog
Contact us
Submit
Question #179135
Evaluate the indefinite integral in each item
∫e
2x+1
dx
∫1/(1+e
x
) dx
∫e
2x
/(e
x
+3) dx
∫4(10
2x^2
) dx
∫x
2
/(x
3
+5) dx
Expert's answer
∫
e
2
x
+
1
d
x
=
1
2
∫
e
2
x
+
1
d
(
2
x
+
1
)
=
1
2
e
2
x
+
1
+
C
,
C
∈
R
\int e^{2x+1}dx=\frac12\int e^{2x+1}d(2x+1)=\frac12e^{2x+1}+C,C\in{\mathbb{R}}
∫
e
2
x
+
1
d
x
=
2
1
∫
e
2
x
+
1
d
(
2
x
+
1
)
=
2
1
e
2
x
+
1
+
C
,
C
∈
R
.
∫
d
x
e
x
+
1
\int\frac{dx}{e^x+1}
∫
e
x
+
1
d
x
. We make the change:
z
=
e
x
z=e^x
z
=
e
x
. We point out that
z
>
0
z>0
z
>
0
. We receive:
∫
d
z
z
(
z
+
1
)
=
∫
(
1
z
−
1
z
+
1
)
d
z
=
l
n
z
−
l
n
(
z
+
1
)
+
C
=
x
−
l
n
(
e
x
+
1
)
+
C
,
C
∈
R
\int\frac{dz}{z(z+1)}=\int(\frac{1}{z}-\frac{1}{z+1})dz=ln\,z-ln(z+1)+C=x-ln(e^x+1)+C,C\in{\mathbb{R}}
∫
z
(
z
+
1
)
d
z
=
∫
(
z
1
−
z
+
1
1
)
d
z
=
l
n
z
−
l
n
(
z
+
1
)
+
C
=
x
−
l
n
(
e
x
+
1
)
+
C
,
C
∈
R
∫
e
2
x
e
x
+
1
d
x
\int\frac{e^{2x}}{e^x+1}dx
∫
e
x
+
1
e
2
x
d
x
. We make the change
z
=
e
x
z=e^x
z
=
e
x
and receive:
∫
z
d
z
z
+
1
=
∫
(
1
−
1
z
+
1
)
d
z
=
z
−
l
n
(
z
+
1
)
+
C
=
e
x
−
l
n
(
e
x
+
1
)
+
C
,
C
∈
R
\int\frac{zdz}{z+1}=\int(1-\frac{1}{z+1})dz=z-ln(z+1)+C=e^x-ln(e^x+1)+C,C\in{\mathbb{R}}
∫
z
+
1
z
d
z
=
∫
(
1
−
z
+
1
1
)
d
z
=
z
−
l
n
(
z
+
1
)
+
C
=
e
x
−
l
n
(
e
x
+
1
)
+
C
,
C
∈
R
∫
4
(
1
0
2
x
2
)
d
x
=
∫
4
e
2
x
2
l
n
2
d
x
.
\int 4(10^{2x^2})dx=\int4e^{2x^2ln2}dx.
∫
4
(
1
0
2
x
2
)
d
x
=
∫
4
e
2
x
2
l
n
2
d
x
.
The good expression for this integral in terms of elementary functions is not known.
∫
x
2
x
3
+
5
d
x
=
∫
1
3
(
x
3
+
5
)
d
(
x
3
+
5
)
=
3
l
n
(
x
3
+
5
)
+
C
,
C
∈
R
.
\int\frac{x^2}{x^3+5}dx=\int\frac{1}{3(x^3+5)}d(x^3+5)=3ln(x^3+5)+C,C\in{\mathbb{R}}.
∫
x
3
+
5
x
2
d
x
=
∫
3
(
x
3
+
5
)
1
d
(
x
3
+
5
)
=
3
l
n
(
x
3
+
5
)
+
C
,
C
∈
R
.
Our fields of expertise
Programming
Math
Engineering
Economics
Physics
LATEST TUTORIALS
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
#339914
on Dec 2023
Read all reviews >>