Question

Find the horizontal and vertical components of a force of 120𝑁 that acts in a direction forming a 58° with the vertical.

Answer 1

$F = 120 \; N$ , $\alpha =58^\circ$

The horizontal component:

$F_x = 120 \cdot \cos 58^\circ = 120 \cdot 0.53 = 63.6\; N$

The vertical component:

$F_y = 120 \cdot \sin 58^\circ = 120 \cdot 0.848 = 101.76 \; N$