𝑓(𝑥) = 9 𝑙𝑜𝑔 (𝑥) + 12 ln (2𝑥 + 1)
Given f(x)=9logx+12ln(2x+1)f(x)=9 log x+12 ln(2x+1)f(x)=9logx+12ln(2x+1)
Which may be written as
f′(x)=d/dx[9lnx/ln10+12ln(2x+1)]f'(x)=d/dx [9lnx/ln10+12 ln(2x+1) ]f′(x)=d/dx[9lnx/ln10+12ln(2x+1)]
=9/ln10(d(lnx))/dx+12d[ln(2x+1)]/dx=9/ln10 (d(ln x))/dx+12 d[ln(2x+1)]/dx=9/ln10(d(lnx))/dx+12d[ln(2x+1)]/dx
=9/(xln10)+12(2/(2x+1))= 9/(xln 10)+12(2/(2x+1))=9/(xln10)+12(2/(2x+1))
=9/(xln10)+24/(2x+1)=9/(xln 10)+ 24/(2x+1)=9/(xln10)+24/(2x+1)
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