Answer to Question #179766 in Calculus for Nora

Question #179766

𝑓(𝑥) = 9 𝑙𝑜𝑔 (𝑥) + 12 ln (2𝑥 + 1)


1
Expert's answer
2021-04-25T17:07:38-0400

Given  f(x)=9logx+12ln(2x+1)f(x)=9 log⁡ x+12 ln⁡(2x+1)

Which may be written as 

f(x)=d/dx[9lnx/ln10+12ln(2x+1)]f'(x)=d/dx [9lnx/ln10+12 ln⁡(2x+1) ]

=9/ln10(d(lnx))/dx+12d[ln(2x+1)]/dx=9/ln⁡10 (d(ln x))/dx+12 d[ln⁡(2x+1)]/dx

=9/(xln10)+12(2/(2x+1))= 9/(xln 10)+12(2/(2x+1))

=9/(xln10)+24/(2x+1)=9/(xln 10)+ 24/(2x+1)


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