Find the derivative of y= sinx/2+cotx
Find the derivative of "y=\\sin{\\frac{x}{2}}+\\cot{x}"
Solution:
"y'=\\frac12\\cos{\\frac {x}{2}}-\\frac{1}{\\sin^2{x}}"
Answer:
"y'=\\cos{\\frac {x}{2}}\\cdot(\\frac x2)'-\\frac{1}{\\sin^2{x}}=\\frac12\\cos{\\frac {x}{2}}-\\frac{1}{\\sin^2{x}}" .
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