Question #151781
Using the ε-N definition of convergence of sequences, prove that limit of (2/n) when n goes to infinity is 0.
1
Expert's answer
2020-12-21T18:58:42-0500

We begin by examining the size of the difference:

2n0=2n\big|\dfrac{2}{n}-0\big|=\dfrac{2}{n}

Given ε>0\varepsilon>0


2n0=2n<ε,if n>2ε\big|\dfrac{2}{n}-0\big|=\dfrac{2}{n}<\varepsilon, \text{if}\ n>\dfrac{2}{\varepsilon}

Therefore using the limit definition


limn(2n)=0\lim\limits_{n\to \infin}(\dfrac{2}{n})=0

The sequence converges to  when nn goes to infinity.



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