Given that,
f(x,y)=(2x−x2)(8y−y2)Clearly f∈C∞ , thus Critical points are given by
∇f(x,y)=((2−2x)(8y−y2),(2x−x2)(8−2y))=(0,0) Then we get,
(2−2x)(8y−y2)=0(2x−x2)(8−2y)=0 After solving the above equation we get the critical points are ,
(0,0),(0,8),(1,4),(2,0),(2,8) Now, calculate the Hessian matrix
Hf(x,y)=[fxxfyxfxyfyy] Thus in this case we get
Hf(x,y)=[−2(8y−y2)4(1−x)(4−y)4(1−x)(4−y)−2(2x−x2)] Thus, Hf(0,0),Hf(0,8),Hf(2,0),Hf(2,8) are indefinite as eigen values are ±4 , thus (0,0) ,(0,8),(2,8) are a saddle point.
Similarly, Hf(1,4) is negative definite as eigen values are -2,-32,thus (1,4) is point of minima.
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