We shall find the angle between the curves y 2= ax and ay2 = x 3
Consider the equations of the curves;
y 2 = ax and ay2 = x 3
Rewrite the equations
y 2 = ax and y 2 = x3/a,
ax = x3/a,
x 2 = a 2,
x = a,
y = (ax) 1/2 = x.
Since x = a; y = a,
the points of contacts = (a, a)
We differentiate
y 2 = ax,
2y dy/dx= a,
dy/dx= a/(2y),
M1 = 1/2,
ay2 = x 3,
2ay dy/dx= 3x 2,
dy/dx = 3/2
M2 = 3/2
So;
tanᶱ = | (m1 – m2)/ (1 + m1*m2) |
= | ( 1/2–3/2 )/ (1 + ½*3/2)
= |-4/7| = 4/7
ᶱ =tan-1(4/7 )
ᶱ = 29.74◦
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