Question #121154
The vector field F(x,y,z)=⟨2ze^(xy),xy^2z,sin(x+y)cos(z)⟩

is continuous on
Select one:
a. only the point (0,0)
.
b. all of R^2
.

c. all of R^3
.
d. all of R
.
1
Expert's answer
2020-06-14T18:27:19-0400

Given F(x,y,z)=<2zexy,xy2z,sin(x+y)cos(z)>F(x,y,z)=<2ze^{xy},xy^2z,sin(x+y)cos(z)> .

Since Polynomial ,ex,sin(x),cos(x), e^x, sin(x), cos(x) are continuous everywhere, so their composition is also continuous.

Thus, each component of F(x,y,z) are continuous for all (x,y,z)(R,R,R)=R3(x,y,z)\in (\R,\R,\R)=\R^3 .

Hence, option (c) is the correct option.


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