By direct computations(see e.g., https://www.math.com/tables/integrals/tableof.htm), we get:
∫f(x,y)dx=∫yxdx=y∫1xdx=y ln∣x∣+g(y)\int f(x,y)dx=\int\frac{y}{x}dx=y\int\frac{1}{x}dx=y\,ln|x|+g(y)∫f(x,y)dx=∫xydx=y∫x1dx=yln∣x∣+g(y)
Answer: b). y ln∣x∣+g(y)y\,ln|x|+g(y)yln∣x∣+g(y)
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