It is necessary to find the first approximation of the function f(x)=(1−x)100 near x=0?
The first approximation of the function is a line with the equation y−y0=k(x−x0), where x0=0 by the condition. y0=f(x0)=(1−0)100=1.
To find k we must find the first derivative of f(x) and substitute x0=0. So:
dxdf(x)=−100(1−x)99
Then:
k=dxdf(x0)=−100(1−0)99=−100
Write an equation of the straight line:
y−1=−100x
Answer: the first approximation of the function f(x)=(1−x)100 is the line y=−100x+1.
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