If the percent error in the length of pendulum is 3%3\%3% .
As,
∆TT×100=12∆ll×100\frac{∆T}{T}\times100=\frac{1}{2}\frac{∆l}{l}\times100T∆T×100=21l∆l×100
So, percent error in time period=12×3%=1.5%=\frac{1}{2}\times3\%=1.5\%=21×3%=1.5% .
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