Solution:
a) there are at least two ways of describing the set {7,8....} is true, for example
"{{x| x \\in {N}, x \\ge 7}}"b) any function with domain R X R is a binary operation is false, because a binary operation is a mathematical operation that takes two arguments and returns one result (that is, with arity two);
c) the graph of every function from [0,1] to R is infinite is false, since not every function is defined in the specified interval;
d) The function f: R --> R , defined by f(x)= x|x| , is an odd function is true
"f(-x)=-f(x)"
e) the domain of the function f ° g ,where f(x) = √x and g(x) = √ 2-x , is [- infinity,2] is true
"f\\degree g= \\sqrt {\\sqrt{2-x}}=\\sqrt [4]{2-x}""2-x \\ge0"
"x \\leq2"
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Dear Neelabh Mam, thank you for leaving a feedback.
d) The function f: R --> R , defined by f(x)= x|x| , is an odd function is true because x|x| is composed of multiplication of an odd and and even function viz x and |x|. By the basic properties of even-odd function multiplication, the product of an odd and and even function is an odd function
Dear mamn. Thank you for leaving a feedback.
(a) we need to give 2 examples. second one could be : { x - 2 | x ∈ Z+, x >= 9 } (b) we are given a valid function with domain RxR and an unknown range. The question is if this is a binary operation. A binary operation on R defines a function from RxR to R. Although the domain is specified to be R, the range is not specified to be R, hence this statement is generally false as in: for the binary operation a * b = sqroot(a + b) would result in imaginary numbers for say a = -1 , b = -2 etc
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