Define the function "f(x)=x^5-x^3+3x-5." The function "f(x)" is continuous on the closed interval "[1, 2]" as polynomial.
"f(2)=2^5-2^3+3(2)-5=25>0"
By the Intermediate Value Theorem "f" must have a zero between "1" and "2."
Hence the Intermediate Value Theorem can be applied to show that there is a root of the
equation "x^5-x^3+3x-5=0" in the given interval "[1,2]."
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