Area of square is A(s)=s2.A(s)=s^2.A(s)=s2.
To determine the rate change of its area with respect s, take the derivative of A.
dAds=2s.\frac{dA}{ds}=2s.dsdA=2s.
Note it is the same as A'. So,
A′(s)=2s.A'(s)=2s.A′(s)=2s.
Then, substitute the given value of s.
A′(8)=2(8)=16.A'(8)=2(8)=16.A′(8)=2(8)=16.
Answer:
The rate of change of area with respect to sss when s=8s=8s=8 is 16.
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