Given the two planes x - y + 2z = 0 and 3x + 2y - 6z + 4 = 0. Find a parametric equation for the intersection.
If two planes intersect, they intersect in a line.
Setting "z=t," we can find the equation of the line.
"x-y+2z=0\\\\\n\\implies x-y+2t=0\\\\\n\\implies x-y=-2t\\\\"
"3x+2y-6z+4=0\\\\\n\\implies 3x+2y-6t+4=0\\\\\n\\implies 3x+2y=-4+6t"
"2x-2y=-4t\\\\\n3x+2y=-4+6t\\\\\n5x=-4+2t\\\\\nx=-0.8+0.4t\\\\\ny=x+2t=-0.8+0.4t+2t=-0.8+2.4t."
The parametric equation for the intersection:
"x=-0.8+0.4t,y=-0.8+2.4t,z=t."
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