Question #252861

Find the equation of the ellipse in standard form whose Foci is (2,7) and (-2,7) and the length of the major axis is 6


Expert's answer

The center is located midway between the vertices on the major axis:

center=((2+(−2)2,7+72)=(0,7)(\frac{(2+(-2)}{2},\frac{7+7}{2})=(0,7)

length of major axis= 6=2a

  ⟹  a=3\implies a=3

c2=a2−b2c=2,a=322=32−b2b2=9−4=5b=5c^2=a^2-b^2\\ c=2,a=3\\ 2^2=3^2-b^2\\ b^2=9-4=5\\ b=\sqrt 5

The standard form equation of the ellipse is (x−h)2a2+(y−k)2b2=1\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

x29+(y−7)25=1\frac{x^2}{9}+\frac{(y-7)^2}{5}=1




LATEST TUTORIALS
APPROVED BY CLIENTS